252. Meeting Rooms

Given meeting time intervals, decide whether one person can attend all of them (no two meetings overlap).

After sorting by start, a conflict must involve neighbors: check whether each meeting starts before the previous one ends.

1function canAttendMeetings(intervals: number[][]): boolean {
2  intervals.sort((a, b) => a[0] - b[0]);
3  for (let i = 1; i < intervals.length; i++) {
4    if (intervals[i][0] < intervals[i - 1][1]) return false;
5  }
6  return true;
7}

meetings

[0,30]

[5,10]

[15,20]

030

Sort by start time.

1 / 0

Space: play/pause · ←/→: step